8p^2=98

Solution for 8p^2=98 equation:

8p^2=98

We move all terms to the left:

8p^2-(98)=0

a = 8; b = 0; c = -98;
Δ = b2-4ac
Δ = 02-4·8·(-98)
Δ = 3136
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}$

$\sqrt{\Delta}=\sqrt{3136}=56$
$p_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(0)-56}{2*8}=\frac{-56}{16}
=-3+1/2
$
$p_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(0)+56}{2*8}=\frac{56}{16}
=3+1/2
$